How it is implemented technically
Covering all possible combinations
One can ask: "How to cover all combinations if every time random value will be taken?". The answer can be given based on probability theory. Let say 1 million combinations (N) should be covered. The program will try to cover them by random generator. The probability that 1 particular value is covered in 1 attempt (iteration) is 1/N or 1/1000000 in this example. If 1 million attempts will be taken, the probability of covering all 1 million values is 63%. It can be calculated from this logic:
Probability, that one particular value is not covered in one attempt is 1 - 1/N.
Probability, that one particular value is not covered in N attempts is (1 - 1/N)N.
Probability, that one particular value is covered in N attempts is 1 - (1 - 1/N)N. This value for N more than 50 always approximately equals to 63%. And for 5*N attempts, the probability will be 1 - (1 - 1/N)5N which equals to 99%. In other words, 1 million values can be covered by random brute force with probability 99% if 5 million attempts will be taken.
Reasons why people should do it
- Help to make new step in science
- Get some money! If there will be any cash prize for the findings (Nobel Prize for Gravity-Electromagnetism relation or Millenium Prize from Clay Mathematics Institute for Disproof of the Riemann hypothesis), the person who will find it will get 10% of this amount.
For now, only 2 tasks are supported, but this list can be extended in the future. These 2 tasks are "Finding Gravity and Electromagnetism relation" and "Disproof of Riemann hypothesis". The main limitation is: task should not require strong relation with previous results. Like password brute force is an ideal task for this kind of computing. This approach cannot help with the tasks where next step can be calculated only based on previous step result.
Small step to Unified Field Theory or Gravity and Electromagnetism relation
Many scientists try to find so-called Unified Field Theory. The term was coined by Einstein. The goal of this theory is finding a relation between all known fields like gravity, electromagnetism etc. Let’s start from something small, for example, find the relation between gravitational constant G and electromagnetic constants ε0 (Vacuum permittivity), μ0 (Vacuum permeability) and some other constants like π number, Planck's constant, Elementary charge (electron charge), Boltzmann constant. Here full random brute force method is suggested in order to find this relation. This task had many different changes, which were described in this old post.
Why there is a chance to find something interesting?
Fairly often in the history, scientists just guessed correct equations or discovered something accidentally. There is an opinion, that even Einstein just guessed his famous formula E=mc2. In this sense why not to try again, especially now with modern technology new approaches can be used. There is no Einstein nowadays, but there are computers, which can partially replace his very smart brain.
G – Gravitational constant (6.67408×10-11)
ε0 – Vacuum permittivity (8.85418781762×10-12)
μ0 – Vacuum permeability (1.2566370614359×10-6)
h – Planck constant (6.626070040×10-34)
e – Elementary charge (electron charge) (1.6021766208×10-19)
m, n – integer number, which can be from 2 to 15. It is needed to cover some cases like 3/2*Something and etc, which often appears in physical equations
π – Pi number (3.14159265…)
a, b, c, d, f, g, j – exponents which can be -5, -9/2, -4, -7/2, -3, -5/2, -2, -3/2, -1, -1/2, 0, 1/2, 1, 3/2, 2, 5/2, 3, 7/2, 4, 9/2, 5. These are commonly used in physics exponents and cover most of the cases like
How long will it take?
With the normal modern computer and default settings in Google Chrome browser, this program can perform around 6000 validation of equation (1) per second. The number of combinations now 3.5×1011 or 350 billion. Total calculation time for one computer with 5 times overhead will be 18 years and for 10000 computers it is just 16 hours.
Disproof of the Riemann Hypothesis
Riemann Hypothesis was stated more than 150 years ago (in 1859) by Mr Riemann. It tells about zeroes distribution of the Riemann zeta function. Many mathematicians of the world are struggling over its proof, but during last 150 years, nobody could prove it. Clay Mathematics Institute gives 1000000 dollars for the proof or disproof of this hypothesis, like one of the Millennium Prize Problems. My last experience shows, that proving something is not my strong skill, but with disproving it is much better. This is why I decided to use this opportunity and try to disprove Riemann Hypothesis :).
What is Riemann Zeta Function and how it will be calculated
This function denoted as ζ and calculated for a complex variable s. Usually, it is written as ζ(s). There are several graphs of the absolute value of this function, depending on the real and imaginary part of the variable s.
Modulus of the Riemann function |ζ(s)|, where real and imaginary part of argument s changing from -10 to 10.
Trivial zeroes of the Riemann Zeta function, where imaginary part of the argument equals to zero, but real part is even negative number -2, -4, -6 etc
Non-trivial zeroes of the Riemann Zeta function, where the real part of the argument equals 1/2, but imaginary part passes different values. Zeroes are located on the red line.
Modulus of the Riemann Zeta function, where the imaginary part of the argument takes values from 10 to 100, and real equals to 0.75.
From the last graph it can be seen, that theoretically at some point Zeta function can reach zero. For better visualisation, there is a video, where it is demonstrated in which case Riemann Zeta function can be zero at the point, where the real part of the argument does not equal to 0.5.
This formula is used for the calculations in this program
it was taken from this link (equation (20)). This equation allows calculating values in the range of the real part of the argument from 0 to 1, where the most interesting area of Zeta function is located.
How long will it take?
Currently, this program calculates Riemann Zeta function for the real part of the argument from 0.6 to 0.8 and for the imaginary part from 0 to 1012. If it is assumed, that for covering all combinations it is required to pass real part with step size 0.02, then for real part there will be 10 combinations, but imaginary part pass with the step 0.1, then for the imaginary part it will be 1013 combinations. Total it is 1014 combinations. The average time for calculations of one value of Zeta function is 100 seconds. How it is written above, to cover all combinations with probability 99% by full brute force, it will be required 5 time more combinations. Then for 1 computer time to check all combinations will be 1.59 billion years, and respectively 1 billion computers can do it in 1.59 years. Maybe somebody will be lucky and required value will be found much earlier. Join!